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I am trying to define a new material in silvaco by specifying the NiO parameters.
The example for Ga2O3 was as follows
material material=Ga2O3 user.default=GaN user.group=semiconductor \
affinity=4.0 eg300=4.8 nc300=3.72e18 nv300=3.72e18 permittivity=10.0 \
mun=118 mup=50 tcon.const tc.const=0.13
1. what values should be in the case of NiO?
2. nc300, nv300 means effective density of states?
3. mun, mup means electron and hole mobility?
4. tcon.const tc.const means dielectric constant?
5. user.default=GaN user.group=semiconductor \ I want to know the meaning of this part. In the case of NiO, what material should be written in user.default?
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Hi Friend
I'm looking into the same thing. Did you find an answer??
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I am working on ferrites materials. I could see gap, but the problem is that the conduction band minimum crossed the Fermi Level.
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I did try the tb-MBJ. functional too..still the same.
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I am interested in calculating the carrier concentration of both n-type and p-type semiconductors by using the Mott- Schottky plot. I would be very grateful if you could give me some suggestions for the calculation of carrier concentration for n-type S/C, and how to calculate the value of (1/c^2). Thank you.
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Dear Dr. Janak Paudel ,
The following notes may be useful:
!Let’s break down the information you’re looking for:
  1. Mott-Schottky Plot and Carrier Concentration: The Mott-Schottky plot is a useful tool in semiconductor electrochemistry. It describes the reciprocal of the square of capacitance versus the potential difference between bulk semiconductor and bulk electrolyte. For n-type semiconductors, the Mott-Schottky plot is linear. It allows us to determine system properties such as flat band potential, doping density, or Helmholtz capacitance. The formula to calculate the intrinsic carrier concentration (N_i) in an intrinsic semiconductor is: [ N_i = \sqrt{N_c \cdot N_v} \cdot e^{-\frac{E_g}{2kT}} ] where:(N_c) is the effective density of states in the conduction band. (N_v) is the effective density of states in the valence band. (E_g) is the band gap energy. (T) is the absolute temperature. (k) is the Boltzmann constant.
  2. n-Type Semiconductor Carrier Concentration: If the concentration of donor atoms (ND) is greater than the concentration of acceptor atoms (NA), the semiconductor material is n-type. In this case, the concentration of electrons (n) is greater than the concentration of holes (p): [ n = N_D - N_A ] The intrinsic carrier concentration (ni) can be calculated as: [ n_i = \sqrt{\frac{N_c \cdot N_v}{n}} ]\where (N_c) and (N_v) are the effective density of states in the conduction and valence bands, respectively.
  3. Value of (1/c^2): The term (\frac{1}{c^2}) is related to the Mott-Schottky plot. It represents the reciprocal of the square of the semiconductor electrode capacitance (CSC). Under depletion conditions, there is a relation between (\frac{1}{C_{SC}^2}) and the potential (V): [ \frac{1}{C_{SC}^2} = \frac{2}{\varepsilon \varepsilon_0 e N_D} \left(E - E_{fb} - \frac{kT}{e}\right) ] where:(\varepsilon) is the permittivity. (e) is the elementary charge.
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It is okay that more mass loading may increase resistance and therefore capacitance will be less. However, what should happen ideally when we increase mass loading?
If I use very less mass loading, will it give better results?
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every time i calcualte the specific capacitence it comes less than 50. dicharge time also comes in 5 to 15 seconds? what is possible reason for this. I am using glassy carobn electrode with 0.07cm2 area?it is the imapct of low mass loading? kindly guide?hihgly appreciated. i am using sp-300 biologic potentiostae and techiques for the GCD is gpcl2?
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It is very well known that, owing to the soft lattice, and ionic bonds, metal halide perovskites shows easy movements of different ionic species under external perturbation. Due to this the materials shows mixed electro ionic conduction.
My question is that, is there any experimental method that can distinguish between the ionic and electronic component of the total conductance?
How one can separately measure these two (electronic and ionic) conductance?
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Hey there Subham Paramanik!
You've Subham Paramanik hit on a crucial point about metal halide perovskites. Their soft lattice and ionic bonds indeed contribute to mixed electro-ionic conduction, making it essential to distinguish between electronic and ionic components.
Fortunately, several experimental methods can help in this regard. One common approach involves impedance spectroscopy, where frequency-dependent measurements can reveal distinct responses from electronic and ionic processes. By analyzing the impedance spectra at different frequencies, one can separate out the contributions of electronic and ionic conductance.
Another method is to employ temperature-dependent conductivity measurements. Since electronic and ionic conductivities often have different activation energies, varying the temperature can selectively enhance one type of conductivity while suppressing the other. This allows for the determination of their individual contributions to the total conductance.
Additionally, techniques such as Hall effect measurements and transient current analyses can provide valuable insights into the nature of charge transport, aiding in the separation of electronic and ionic conductivities.
By combining these experimental methods judiciously, researchers can effectively disentangle the electronic and ionic contributions to the overall conductivity in metal halide perovskites, paving the way for a deeper understanding of their fascinating properties.
Hope this helps! If you Subham Paramanik need more details or have further questions, feel free to ask. Let's dive deeper into this fascinating topic!
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Can you please tell me the theory of semiconductor ceramics: introduction, properties, manufacturing methods and applications ?
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Check out the reference list in this online article:
Advanced ceramics - the new frontier in modern-day technology: Part I (scielo.org.za)
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Research papers have discussed the phenomenon of both types of heterostructures. My question is: is there a theoretical threshold for the conduction band (CB) and valence band(VB) potential difference of two semiconductors to form these heterostructures?
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The formation of Z-scheme and Type-II heterostructures in semiconductors involves specific theoretical criteria related to the conduction band (CB) and valence band (VB) potential differences. Let’s delve into the details:
  1. Z-Scheme Heterostructure: The Z-scheme heterostructure is characterized by a staggered alignment of energy bands between two semiconductors. It plays a crucial role in photocatalysis and solar energy conversion. Criteria: Band Alignment: The CB of one semiconductor should be higher than the CB of the other, while the VB of the second semiconductor should be higher than the VB of the first. Electron and Hole Transfer: Efficient electron transfer from one semiconductor’s CB to the other’s VB (forming an electron–hole pair) is essential. Interlayer Recombination: The energy difference between the CB and VB levels should allow for minimal interlayer electron–hole recombination. Threshold: There isn’t a strict theoretical threshold, but a significant energy difference is necessary for efficient charge separation and overall performance.
  2. Type-II Heterostructure: In a Type-II heterostructure, the CB of one semiconductor aligns with the VB of the other, resulting in a staggered band arrangement. Criteria: Band Offsets: The CB and VB levels of the two semiconductors should exhibit a significant offset. Charge Separation: The energy difference should facilitate efficient charge separation, preventing rapid recombination. Potential Gradients: The built-in electric field at the interface should drive charge carriers away from each other. Threshold: Again, there’s no fixed threshold, but substantial band offsets are required for effective charge separation and photocatalytic activity1.
  3. Density Functional Theory (DFT): Researchers often use DFT calculations to predict and understand the band alignment in heterostructures. Predictions: DFT can reveal whether a given combination of semiconductors will exhibit Z-scheme or Type-II behavior based on their electronic structures. Materials Design: DFT helps identify promising heterojunctions for photocatalysis and energy conversion.
In summary, while there’s no strict numerical threshold, the relative positions of CB and VB levels significantly influence the formation and performance of Z-scheme and Type-II heterostructures. Researchers continue to explore novel combinations and optimize band alignments for efficient energy conversion.
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I want know more about relationship between carrier concentration and band gap on semiconductor or metal oxides.
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Janak Paudel, Larger bandgap typically corresponds to a lower intrinsic carrier concentration, while a smaller bandgap results in a higher intrinsic carrier concentration. This relationship is due to the energy required to promote electrons from the valence band to the conduction band.
  • Altermatt, P. P., Schenk, A., Geelhaar, F., & Heiser, G. (2003). Reassessment of the intrinsic carrier density in crystalline silicon in view of band-gap narrowing. Journal of Applied Physics, 93(3), 1598-1604.
  • Walukiewicz, W. (2001). Intrinsic limitations to the doping of wide-gap semiconductors. Physica B: Condensed Matter, 302, 123-134.
  • Alberi, K., & Scarpulla, M. A. (2018). Effects of excess carriers on charged defect concentrations in wide bandgap semiconductors. Journal of Applied Physics, 123(18).
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Does conductivity increase with concentration and relationship between semiconductors and both high temperatures and low temperatures?
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A typical semiconductor is a crystalline solid material with an Electrical Conductivity that is highly dependent on temperature. At low absolute temperatures a pure semiconductor will appear to be a good insulator, however, its conductivity rises dramatically as the temperature increases. Electrical currents are transported by ions in a given solution. As the concentration of ions increases, the conductivity increases. This is because conductivity increases as water dissolves more ionic compounds due to the ions transporting an electrical current in the solution.I t might reduce or improve with temperature. In a metal , when temperature increases the resistance increases , due to which resistivity increases and thus , conductivity decreases . Whereas , in case of a semiconductor with increase in temperature , the resistance decreases and thus the conductivity increases .However, conductivity generally only increases with temperature in semiconductors. In metal conductors, increasing the temperature usually results in a decrease in conductivity, or it increases the resistivity. When temperature increases, the vibration of metal ions increases. This results in increase in resistance of metal and hence, decreases in conductivity. In electrolytic conductors, the ions are charge carriers and with increase in temperature, ionization increases and hence, conductivity increases. In semiconductor electron vibration happen at room temperature. But at very low-temperature electron can not get energy and so it can not vibrate and so current cannot pass, so semiconductor act as an insulator. Thus at higher temperatures a semiconductor exhibits properties closer to those of metals. It is the dramatic change in conductivity due to the excitation of valence electrons into the conduction state as the ambient temperature is increased that is the characteristic feature of a semiconductor.
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2024 3rd International Conference on Automation, Electronic Science and Technology (AEST 2024) in Kunming, China on June 7-9, 2024.
---Call For Papers---
The topics of interest for submission include, but are not limited to:
(1) Electronic Science and Technology
· Signal Processing
· Image Processing
· Semiconductor Technology
· Integrated Circuits
· Physical Electronics
· Electronic Circuit
......
(2) Automation
· Linear System Control
· Control Integrated Circuits and Applications
· Parallel Control and Management of Complex Systems
· Automatic Control System
· Automation and Monitoring System
......
All accepted full papers will be published in the conference proceedings and will be submitted to EI Compendex / Scopus for indexing.
Important Dates:
Full Paper Submission Date: April 1, 2024
Registration Deadline: May 24, 2024
Final Paper Submission Date: May 31, 2024
Conference Dates: June 7-9, 2024
For More Details please visit:
Invitation code: AISCONF
*Using the invitation code on submission system/registration can get priority review and feedback
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Useful thing
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Is there a difference in PLQY between direct transition type semiconductors and indirect transition type semiconductors? I am curious about how defects affect PLQY.
Also, what is the difference between Br defect concentration and Cl defect concentration for PLQY?
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Dear Jun Park ,
Let’s delve into the semiconductor properties and their impact on photoluminescence quantum yield (PLQY).
  1. Direct vs. Indirect Band Gap Semiconductors: The band gap represents the minimum energy difference between the top of the valence band and the bottom of the conduction band in a semiconductor. In a direct band gap semiconductor, the top of the valence band and the bottom of the conduction band occur at the same value of momentum. This means that an electron can directly emit a photon when transitioning from the conduction band to the valence band. In an indirect band gap semiconductor, the maximum energy of the valence band occurs at a different value of momentum compared to the minimum energy in the conduction band. Here, an electron must interact with a lattice vibration (a phonon) to either gain or lose momentum during the transition. The difference between direct and indirect band gap semiconductors is most important in optical devices. In direct band gap semiconductors, photons can easily produce electron-hole pairs, while in indirect band gap semiconductors, the process is slower due to the additional momentum change required 1.
  2. Defects and PLQY: Defects play a crucial role in determining the PLQY of semiconductors. Non-radiative recombination losses due to defects can limit the efficiency of light-emitting devices. At low temperatures, defects are frozen out, reducing non-radiative recombination. However, at elevated temperatures, fluctuating defect concentrations can lead to reversible PL intensity loss 2. Defects can act as efficient quenchers, affecting the PLQY. Even a small concentration of such quenchers can substantially reduce the PLQY 3.
  3. Br Defect Concentration vs. Cl Defect Concentration: In perovskite light-emitting diodes (PeLEDs), halide perovskites (such as CsPbBrCl) are promising materials. Chloride vacancies (VCl) in mixed halide compositions (CsPbBrxCl3−x) can lead to lower PLQYs (10-25%) compared to pure CsPbBr or CsPbI nanocrystals (PLQYs over 90%)
  4. The presence of Br defects (bromine-related) or I defects (iodine-related) can significantly impact the PLQY in these materials.
In summary, defects influence PLQY, and understanding their behavior is essential for optimizing semiconductor devices. Researchers continue to explore ways to suppress non-radiative recombination and enhance efficiency in light-emitting devices.
You
Is there a difference in PLQY between direct transition type semiconductors and indirect transition type semiconductors? I am curious about how defects affect PLQY. Also, what is the difference between Br defect concentration and Cl defect concentration for PLQY?
Let’s explore the fascinating world of semiconductor properties and their impact on photoluminescence quantum yield (PLQY).
  1. Direct vs. Indirect Band Gap Semiconductors: The band gap represents the minimum energy difference between the top of the valence band and the bottom of the conduction band in a semiconductor. In a direct band gap semiconductor, the top of the valence band and the bottom of the conduction band occur at the same value of momentum. This means that an electron can directly emit a photon when transitioning from the conduction band to the valence band. In an indirect band gap semiconductor, the maximum energy of the valence band occurs at a different value of momentum compared to the minimum energy in the conduction band. Here, an electron must interact with a lattice vibration (a phonon) to either gain or lose momentum during the transition. The difference between direct and indirect band gap semiconductors is most important in optical devices. In direct band gap semiconductors, photons can easily produce electron-hole pairs, while in indirect band gap semiconductors, the process is slower due to the additional momentum change required 1.
  2. Defects and PLQY: Defects play a crucial role in determining the PLQY of semiconductors. Non-radiative recombination losses due to defects can limit the efficiency of light-emitting devices. At low temperatures, defects are frozen out, reducing non-radiative recombination. However, at elevated temperatures, fluctuating defect concentrations can lead to reversible PL intensity loss 1. Defects can act as efficient quenchers, affecting the PLQY. Even a small concentration of such quenchers can substantially reduce the PLQY 2.
  3. Br Defect Concentration vs. Cl Defect Concentration: In perovskite light-emitting diodes (PeLEDs), halide perovskites (such as CsPbBrCl) are promising materials. Chloride vacancies (VCl) in mixed halide compositions (CsPbBrxCl3−x) can lead to lower PLQYs (10-25%) compared to pure CsPbBr or CsPbI nanocrystals (PLQYs over 90%) 3. The presence of Br defects (bromine-related) or I defects (iodine-related) can significantly impact the PLQY in these materials.
In summary, defects influence PLQY, and understanding their behavior is essential for optimizing semiconductor devices. Researchers continue to explore ways to suppress non-radiative recombination and enhance efficiency in light-emitting devices.
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i understand, a longer carrier lifetime is better for photodetector than short one.
non-radiative semiconductor has longer carrier lifetime than radiative semiconductor.
nevertheless, why radiative semiconductor is preferred than non-radiative?
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Most photodectors are silicon and germanium based, and that are indirect bandgap semiconductors. Direct gap semiconductors e.g. GaAs or GaP are used too for suitable wavelength however their problem might be too shallow depth of absorption for some light wavelength because of direct bandgap.
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Does semiconductor behaves as conductor at high temperature and why electrical conductivity of a metal decreases with temperature?
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The electrical conductivity of semiconductors increases with increasing temperature because, with increase in temperature, number of electrons from the valence bond can jump to the conduction band in semiconductors. When temperature increases, the vibration of metal ions increases. This results in increase in resistance of metal and hence, decreases in conductivity. In electrolytic conductors, the ions are charge carriers and with increase in temperature, ionization increases and hence, conductivity increases. In the case of semiconductors, as temperature increases, electrons in the valence band acquire sufficient energy to be promoted across the "energy gap" into the conduction band. When this occurs, these promoted electrons can move and conduct electricity. Hence intrinsic semiconductor behaves like an insulator. Hence as temperature increases, more and more hole and electron pairs are generated and after a certain temperature and it will behave as ideal conductors. The general rule says that resistance increases in conductors with increasing temperature and decreases with increasing temperature in insulators. In the case of semiconductors, typically, the resistance of the semiconductor decreases with the increasing temperature. At room temperature some covalent some covalent bond breaks and semiconductor behaves slightly as a conductor. The gap between conduction band and valence band is small in semiconductors. Therefore, electrons from the valence band can jump to the conduction band on increasing temperature. Thus, they become more conducting as the temperature increase. The hotter a material, the more its atoms or ions jiggle about and the harder it is for electrons to wriggle through, which translates into higher electrical resistance. The electrical conductivity of a metal decreases with increase in temperature because the thermal energy increases the collision of electrons and disturbs the free flow.
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Does the energy gap in a semiconductor increase with temperature and what happens if the band gap of solar cell material increases?
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Hi Sir
An increase in temperature will always affect the semiconductor properties (semiconductors are sensitive to temperature) i.e., reduce the bandgap of the semiconductor where the energy needed for the excitation of electrons will be smaller, which results in reduced open circuit voltage (Voc) and efficiency of solar cells. The solar cell's power output directly depends on quasi-Fermi level separation, i.e., Voc. Though, the decrease in bandgap extends the absorption range and increases the short-circuit current (Jsc) of the solar cell, but also decreases the open-circuit voltage (Voc) of the device, thus a half-and-half situation arises for the optimization of the semiconductor material. So Normally, the standard test condition of solar cells in the laboratory is done at 25 degrees Celsius to avoid temperature effects.
You can also refer this article,
Simultaneously Decreasing the Bandgap and Voc Loss in Efficient Ternary Organic Solar Cells.
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How does the conductivity vary with temperature for an extrinsic semiconductor and relationship between temperature and conductivity in metals?
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Electrical conductivity increases in semiconductors with increasing temperature, because, as temperature increases, the number of electrons from the valence band is able to jump to the conduction band. The electrical conductivity of an extrinsic semiconductor increases with a rise in temperature such that semiconductors have a negative temperature coefficient of resistance. With increase in temperature of extrinsic semiconductor, minority charge carriers increase because of bond breakage and minority charge carriers may become almost equal with majority charge carriers. Thus, extrinsic semiconductor behaves almost as an intrinsic semiconductor with increase in temperature. Clearly, conductivity significantly depends on majority charge carriers generated due to impurity doping. It means conductivity of metal is highly dependent on free electrons. If we increase the temperature of metal then lattice vibration increase so restrictions in the path of free electrons also increases. So conductivity increase by lattice vibration but decrease due to less flow of free electrons. As the temperature of the conductor rises, the velocity of the free-charged particles increases and the increased temperature also affects the amplitude of vibration due to this the vibration rate of metallic atoms also increases.For metals we have positive temperature coefficient of resistance. For semiconductors we have negative temperature coefficient of resistance i.e. as temperature increases then conductivity increases and resistance decreases. The electrical conductivity of semiconductors increases rapidly with increasing temperature, whereas the electrical conductivity of metals decreases slowly with increasing temperature.
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What happens if semiconductor is heated to a very high temperature and how does a semiconductor react to temperature changes what actually happens?
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It melts or decomposes as usual.
But before that, conductivity rises.
Because one can show conductivity is product of charge carrier density and mobility. With temperature, mobility drops as charge carriers are more often scattered by thermal vibrations, but carrier density rises as more and more carriers are given thermal energy to break from bond of individual atoms (like electrons breaking from valence band to conduction band)
For metals, bandgap being practically zero for all purposes, charge carrier density is near-saturated from very low tempertaure, and fall of mobility with rise of temperature contributes to losing conductivity with temperature.
But for semiconductors, charge carrier density is far from saturated, so heating up to a very significant extant (I cannot tell whether virtually all of break-freeable charge carriers set free earlier or the semiconductor melts earlier as temperture keeps rising ) raises chrage carrier density much much more than lost mobility. So, heating raises conductivity of semiconductors
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How does Fermi level change with temperature and relationship between Fermi energy and energy gap in intrinsic semiconductor derivation?
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Hi, you asked so many questions on Fermi levels that I suggest you read a good solid state physics textbook from any university library. An introduction and overview is also available on Wikipedia here:
Thomas
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Why there is gap between conduction band and valence band and position of Fermi level in a type semiconductor?
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Dr Rajesh Parihar thank you for your contribution to the discussion
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What happens to current and voltage when temperature increases and why activity of a semiconductor increases with increase in temperature?
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Dr Clyde Eisenbeis thank you for your contribution to the discussion
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When a pure semiconductor is heated its resistance decreases and mobility of a semiconductor decreases with increase in temperature?
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Dr Armin Dadgar and Dr Jan Martin Wagner thank you for your contribution to the discussion
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Why does voltage decrease when temperature increases in semiconductor and why does a semiconductor device fail due to high temperature?
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Dr Armin Dadgar and Dr Clyde Eisenbeis thank you for your contribution to the discussion
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Can a semiconductor become a superconductor and why does a semiconductor get damaged when a heavy current flows through it?
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More current causes higher temperature, which causes more current. This cycle repeats itself is thermal runaway. Ultimately, the semiconductor is destroyed. This discovery implies that a semiconductor can become a superconductor upon carrier doping. Recently, superconductivity was also discovered in boron-doped silicon and SiC semiconductors. The number of superconducting semiconductors has increased. Superconductivity is the property of certain materials to conduct direct current (DC) electricity without energy loss when they are cooled below a critical temperature (referred to as Tc). These materials also expel magnetic fields as they transition to the superconducting state. When a strong current passes through the semiconductor it heats up the crystal and covalent bond are broken. Hence because of excess number of free electrons it behaves like a conductor. Voltage that is too high can cause premature failure of electrical and electronic components due to overheating. The damage caused by overheating is cumulative and irreversible.
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Is resistance directly proportional to temperature in semiconductor and how increase in temperature affects the conductance of weak electrolytes?
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Dr Vijay Kumar Bodarya thank you for your contribution to the discussion
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Why resistivity of conductor increases with temperature and that of semiconductor decreases with temperature?
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Dr Vijay Kumar Bodarya thank you for your contribution to the discussion
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What is the best conductor of electricity and why does increasing temperature increase the specific resistivity on conductors whereas decrease the specific resistance of semiconductors?
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Dr Naresh,
I'll ask you directly: are you sincere in your interest in the origins of superconductivity or are you simply posting basic questions, hoping for people to answer, and so boost your RG 'score'?
You have posted literally hundreds of basic questions this year, most of which can be resolved with a Google search.
Why?
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Why do superconductors float and why the conductivity of a semiconductor increases with rise in temperature but decreases for metals?
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Meissner effect: All magnetic fields are reflected back from superconductor (a perfect diamagnet) that holds up magnet that emits the magnetic field in first place (provided the field is not too strong to destroy superconductive state).
Earnshaw's theorem says no STATIC arrangement of electric (or magnetic field) can hold up charges in equilibrium, so the floating doesn't happen for two bar magnets
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What is the highest critical temperature of superconductor and when temperature of a semiconductor is increased then its resistance decreases?
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See
Note these
  • As of 2023, the material with the highest accepted superconducting temperature was highly pressurized lanthanum decahydride, whose transition temperature is approximately 250 K (−23 °C) at 200 GPa
  • At standard atmospheric pressure, cuprates currently hold the temperature record, manifesting superconductivity at temperatures as high as 138 K (−135 °C).
  • In 2015, an article published in Nature by researchers of the Otto Hahn Institute suggested that under certain conditions such as extreme pressure H2S transitioned to a superconductive form H3S at 150 GPa (around 1.5 million times atmospheric pressure) in a diamond anvil cell.[9] The critical temperature is 203 K (−70 °C) which would be the highest Tc ever recorded and their research suggests that other hydrogen compounds could superconduct at up to 260 K (−13 °C)
  • On 31st of December 2023 "Global Room-Temperature Superconductivity in Graphite" was published in the journal "Advanced Quantum Technologies" claiming to demonstrate superconductivity at room temperature and ambient pressure in Highly oriented pyrolytic graphite with dense arrays of nearly parallel line defects
Hope these helps
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What is a semiconductor damaged by a strong current and is there any change in the voltage if the temperature of the electrolyte is increased if yes what changes and why?
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Yes, a strong current can damage a semiconductor. Here's why:
  • Heat Generation: When a large current flows through a semiconductor, it encounters resistance within the material. This resistance results in energy being dissipated as heat.
  • Thermal Runaway: As the temperature of the semiconductor increases, its electrical resistance typically decreases. This allows even more current to flow, which in turn generates even more heat. This creates a vicious cycle known as thermal runaway, ultimately leading to excessively high temperatures.
  • Damage Mechanisms: The extreme heat can cause several damaging effects:Breaking of Covalent Bonds: The intense heat can break the covalent bonds holding the atoms of the semiconductor lattice together. This disrupts the material's structure and degrades its electrical properties. Melting: At even higher temperatures, the semiconductor material might melt, permanently destroying its functionality.
Now, let's explore the impact of temperature on electrolytes:
Yes, the voltage of an electrochemical cell (which utilizes an electrolyte) can change with increasing temperature. Here's what happens:
  • Increased Ionic Mobility: As the temperature of an electrolyte rises, the ions within it move more freely due to increased kinetic energy. This enhanced mobility can lead to:Increased Cell Potential: In some cases, the increased ionic movement can improve the efficiency of the cell, leading to a slightly higher voltage. Increased Internal Resistance: However, the increased mobility also contributes to higher internal resistance within the cell. This can counteract the potential increase in voltage, and in some cases, even lead to a decrease in the observed voltage.
The overall impact on voltage depends on the specific type of electrolyte and the chemical reactions involved in the cell. In some cases, the voltage might increase slightly, while in others, it might decrease or remain relatively unchanged.
It's important to note that excessive temperature increases can also be detrimental to electrolytes. High temperatures can:
  • Decompose the electrolyte: This can break down the electrolyte's chemical structure, reducing its conductivity and affecting cell performance.
  • Accelerate corrosion: High temperatures can accelerate the corrosion of electrodes within the cell, further impacting its lifespan and functionality.
Therefore, it's crucial to maintain electrolytes within a recommended temperature range to ensure optimal cell performance and prevent damage.
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Are semiconductors called intrinsic semiconductors and why is thermal conductivity inversely proportional to temperature?
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While "intrinsic semiconductor" is a term used, it's not the only one. Semiconductors can be intrinsic or extrinsic, depending on their doping level:
  • Intrinsic semiconductors: These are pure semiconductors with no dopants added. They have a very low conductivity due to the limited number of free electrons and holes available for carrying current.
  • Extrinsic semiconductors: These are doped semiconductors where impurities are intentionally added to create more free charge carriers, significantly increasing their conductivity compared to intrinsic ones.
Now, about the thermal conductivity and its relation to temperature, the statement is only partially true and depends on the material:
  • Metals: In metals, thermal conductivity is primarily due to the movement of free electrons. As temperature increases, the vibrations of atoms increase, causing more collisions between electrons and hindering their movement. This decreases thermal conductivity with increasing temperature.
  • Non-metals: In some non-metals like crystals, thermal conductivity is due to "phonons," which are vibrations of the atoms themselves. As temperature increases, the number of phonons and their interactions also increase, enhancing thermal conductivity.
Therefore, it's crucial to consider the specific material when discussing the relationship between thermal conductivity and temperature.
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Does conductivity in a semiconductor vary inversely with temperature and relationship between temperature and conductivity for metals and semiconductors?
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The statement that conductivity in a semiconductor varies inversely with temperature is incorrect. In fact, the opposite is true: conductivity in a semiconductor increases with increasing temperature. This is due to the unique band structure of semiconductors.
Here's a breakdown of the relationship between temperature and conductivity for both materials:
Semiconductors:
  • At low temperatures, most electrons are bound to atoms in the valence band.
  • With increasing temperature, some electrons gain enough energy to jump to the empty conduction band, where they are free to move and conduct electricity.
  • This creates more charge carriers (electrons and holes), leading to increased conductivity.
Metals:
  • In contrast, metals already have a large number of free electrons in the conduction band at all temperatures.
  • As temperature increases, the metal atoms vibrate more, causing lattice scattering that disrupts the movement of electrons.
  • This reduces the mobility of electrons and decreases the overall conductivity.
Therefore, the relationship between temperature and conductivity is opposite for semiconductors and metals. While semiconductors become more conductive, metals become less conductive with increasing temperature.
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Does the conductivity of intrinsic semiconductors increase with increasing temperature and how is doping done within a semiconductor to alter their conductivity?
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Conductivity & Intrinsic Semiconductors:
1. Temperature:
The conductivity of intrinsic semiconductors does increase with increasing temperature. This happens because:
  • In an intrinsic semiconductor, at absolute zero temperature, all electrons are in the valence band, and no free electrons are available for conduction, leading to zero conductivity.
  • As the temperature increases, some electrons gain enough thermal energy to jump from the valence band to the conduction band, creating electron-hole pairs.
  • These electron-hole pairs are mobile charge carriers that contribute to electrical conductivity.
  • However, the increase in conductivity is not linear and eventually plateaus as the temperature reaches a certain point.
2. Doping:
Doping is intentionally adding impurities to a semiconductor to alter its conductivity. These impurities introduce additional energy levels within the bandgap, creating more charge carriers and significantly increasing conductivity compared to intrinsic semiconductors.
There are two types of doping:
  • n-type doping: Adding electron donor impurities (elements with more valence electrons) creates additional free electrons and increases conductivity.
  • p-type doping: Adding electron acceptor impurities (elements with fewer valence electrons) creates electron holes (vacant spaces where electrons once resided) and increases conductivity.
Therefore, both increasing temperature and doping can significantly increase the conductivity of intrinsic semiconductors, but they work through different mechanisms.
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Why conductivity of semiconductor increases with temperature and conductivity of semiconductor depends on impurities?
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Semiconductors behave uniquely when it comes to conductivity compared to conductors and insulators, and here's why their conductivity changes with temperature and impurities:
Temperature dependence:
  • Inherent structure: Semiconductors have a unique electronic structure with a filled "valence band" and a higher energy, empty "conduction band." Normally, electrons cannot easily jump this gap, preventing current flow.
  • Thermal excitation: When temperature rises, thermal energy excites some electrons from the valence band to the conduction band. These additional free electrons become mobile charge carriers, increasing conductivity.
Impurity dependence (doping):
  • Pure semiconductors: In their pure state, the number of mobile charge carriers in a semiconductor is very low, resulting in low conductivity.
  • Doping: Introducing controlled impurities, called dopants, drastically alters conductivity. Two main types of doping exist:N-type doping: Adding elements with one extra electron (e.g., phosphorus) creates "donor states" near the conduction band. These readily donate electrons, significantly increasing the number of mobile charge carriers and conductivity. P-type doping: Adding elements with one missing electron (e.g., boron) creates "holes" in the valence band. These "holes" behave like positively charged particles and can move, contributing to current flow and increasing conductivity.
Therefore, both temperature and impurities play a crucial role in determining the conductivity of semiconductors. By manipulating these factors, we can control the flow of electricity in these materials, making them valuable for various electronic applications like transistors and integrated circuits.
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Why resistance is inversely proportional to relaxation time and relationship between conductivity mobility and carrier concentration of a semiconductor?
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Understanding the Relationship between Resistance, Relaxation Time, and Conductivity:
Resistance (R) is a material's opposition to the flow of electric current. In conductors like metals, this opposition arises due to collisions between free electrons (electrons not bound to specific atoms) and the metal's positive ions (atomic cores). These collisions impede the smooth flow of electrons, causing resistance.
Relaxation time (τ) represents the average time between these collisions. Imagine electrons traveling through a corridor with obstacles. The time it takes for an electron to hit one obstacle and then another defines its relaxation time.
The relationship between resistance and relaxation time is:
R ∝ 1/τ (where ∝ represents "proportional to")
This means as the relaxation time increases (fewer collisions), the resistance decreases (easier flow of electrons) and vice versa.
Conductivity (σ) is the inverse of resistance, signifying a material's ability to conduct electricity. It relates to how easily current flows:
σ = 1/R
Therefore, from the first equation, we can also say:
σ ∝ τ
Relating Conductivity, Mobility, and Carrier Concentration in Semiconductors:
Semiconductors are materials with conductivity between conductors and insulators. Their conductivity depends on the number and mobility of charge carriers, typically electrons or holes (vacancies where electrons would be).
Carrier concentration (n) refers to the number of charge carriers per unit volume in the material. More carriers generally lead to more current flow, potentially increasing conductivity.
Mobility (μ) signifies the ease with which these carriers move under an electric field. Carriers with higher mobility experience fewer collisions and move faster, enhancing conductivity.
The relationship between conductivity, mobility, and carrier concentration in a semiconductor is:
σ = n * e * μ
where:
  • e is the charge of an electron (constant)
Therefore, for semiconductors, increasing either carrier concentration or mobility can lead to higher conductivity.
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Why mobility of holes is less than electrons and relationship between conductivity and temperature in semiconductors?
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Lower Mobility of Holes:
The mobility of holes in semiconductors is indeed less than the mobility of electrons for two main reasons:
1. Effective Mass: In solids, electrons and holes behave like particles with an effective mass, which can be different from their actual mass. The effective mass often depends on the material's band structure and how electrons interact with the lattice. Generally, the effective mass of holes in semiconductors is greater than the effective mass of electrons. This larger mass makes it harder for holes to accelerate under an electric field, leading to lower mobility.
2. Scattering Mechanisms: Semiconductors have imperfections like dopant atoms and lattice vibrations that can scatter both electrons and holes as they move. However, the way these imperfections interact with each particle can differ. Holes often experience stronger scattering due to their interaction with the surrounding positive ions and the fixed atomic positions they "hop" between. This additional scattering further hinders their mobility compared to electrons.
Conductivity and Temperature in Semiconductors:
The conductivity of a semiconductor, which measures its ability to conduct electricity, is related to temperature in a non-linear way:
  • As temperature increases:Thermal excitation: More electrons gain enough thermal energy to jump from the valence band to the conduction band, increasing the number of free electrons and holes contributing to conduction. This increases conductivity. Increased scattering: However, the higher temperature also intensifies the thermal vibrations in the lattice, leading to more frequent collisions between electrons, holes, and other imperfections. This decreases mobility and partially counteracts the conductivity increase.
Therefore, the overall effect of temperature on conductivity depends on which factor dominates: the increase in carrier concentration or the decrease in mobility. In some cases, the conductivity might initially increase with temperature but then decrease at extremely high temperatures due to the dominance of scattering.
In summary, the lower effective mass and less favorable scattering environment contribute to the lower mobility of holes compared to electrons in semiconductors. Additionally, conductivity in semiconductors exhibits a complex relationship with temperature due to the interplay between carrier concentration and mobility.
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Is conductivity and molar conductivity inversely proportional and how does doping affect the conductivity on intrinsic semiconductor?
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Relationship between Conductivity and Molar Conductivity:
The statement "conductivity and molar conductivity are inversely proportional" is not entirely accurate. They are related, but not in a strictly inverse proportional way. Here's the clarification:
  • Conductivity (κ) measures the ability of a solution to conduct electricity. It depends on the concentration of ions, the type of ions present, and the temperature of the solution. As the concentration of ions increases, conductivity generally increases.
  • Molar conductivity (Λ), on the other hand, is the conductivity of a solution containing one mole of the electrolyte per unit volume and standardized to a path length of one centimeter. It considers the intrinsic ability of the ions to conduct electricity and is partially dependent on concentration.
The key point is that both conductivity and molar conductivity increase with increasing concentration, but not at the same rate. Molar conductivity actually increases more slowly than conductivity with dilution. This is because dilution not only reduces the number of ions per unit volume (decreasing conductivity), but also allows the remaining ions to move more freely (increasing their ability to conduct, hence increasing molar conductivity).
Doping and Conductivity in Intrinsic Semiconductors:
Intrinsic semiconductors are pure materials with relatively low conductivity. Doping, however, significantly affects their conductivity in two ways:
  1. Introducing extrinsic charge carriers: Doping involves introducing impurities (dopant atoms) into the semiconductor lattice. These dopant atoms can either donate or accept electrons, creating additional charge carriers (holes or electrons) compared to the intrinsic case. This increased number of mobile charge carriers directly enhances the conductivity of the material.
  2. Modifying the mobility of charge carriers: Doping can also affect the mobility of the existing charge carriers (holes or electrons) in the semiconductor. Depending on the dopant type and concentration, the mobility can either increase or decrease. Higher mobility allows for easier movement of charge carriers, further contributing to increased conductivity.
Therefore, doping generally increases the conductivity of intrinsic semiconductors by introducing additional charge carriers and potentially modifying their mobility. The specific extent of the increase depends on the type and amount of dopant used.
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Is the conductivity of a semiconductor inversely proportional to the increase in its temperature and difference between lattice scattering and impurity scattering?
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The relationship between temperature and resistance is not directly proportional nor inversely proportional. It's a more complex relationship that depends on the type of material:
  • Conductors: For most conductors like metals, the resistance increases with increasing temperature. This is because the thermal vibrations of atoms in the conductor make it harder for electrons to flow freely, increasing their resistance.
  • Insulators: In contrast, the resistance of insulators generally decreases with increasing temperature. While not as common as in conductors, their internal structure can be affected by temperature, allowing some conduction at higher temperatures.
  • Semiconductors: Semiconductors have a more complex behavior. Their resistance can decrease with increasing temperature due to the creation of additional charge carriers.
Therefore, it's crucial to consider the specific material when analyzing the temperature-resistance relationship.
Relationship between conductivity and molar conductivity with temperature:
  • Conductivity (σ) is the reciprocal of resistance (1/R). So, as resistance increases with temperature (for conductors), conductivity decreases.
  • Molar conductivity (Λ) is conductivity normalized by the concentration of the solution (σ/c). While both conductivity and concentration can be affected by temperature, the overall impact on molar conductivity can be complex and depends on the specific solution and its behavior with temperature.
In summary, the relationship between temperature and resistance is material-dependent, and the changes in con
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Why are transmittance and absorbance inversely proportional and relationship between conductivity mobility and carrier concentration of a semiconductor?
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Dear friend Rk Naresh
Let's delve into the captivating world of semiconductor physics, shall we? Transmittance and absorbance are intricately connected. Light can be either transmitted or absorbed when passing through a material. These actions are inversely related, like a seesaw.
Now, let's talk about conductivity, mobility, and carrier concentration in semiconductors. Picture a bustling city street. Conductivity is akin to the flow of cars, while mobility is the speed limit. Carrier concentration illustrates the number of cars (carriers) on the road.
Conductivity is directly tied to both mobility and carrier concentration. Increasing either mobility or carrier concentration enhances conductivity, similar to more cars speeding down a street resulting in heavier traffic. The relationship between mobility and carrier concentration is not always straightforward. Sometimes, increasing carrier concentration can decrease mobility, and vice versa. Like maneuvering through a crowded street: more people may slow you down, but efficient movement can still lead to high conductivity.
Overall, a semiconductor's conductivity relies on the balance between mobility and carrier concentration, similar to traffic flow depending on both car number and speed. Understanding these connections is crucial for developing and fine-tuning semiconductor devices for various applications.
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What is the relation between Earth’s resistivity and temperature and why does resistivity of semiconductors decrease with increase in temperature?
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Dr Sukru Aktas thank you for your contribution to the discussion
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The dopant concentration is Nd(x) in transiton domain 0<x<a with the Nd(x) being linear, exponential etc with the x. Assuming in equilibrium at temperature T a Fermi-level is constant and equals EF due to what law varies a free carriers concentration n(x)?
Thanx a lot for Your answers and references.
Viktor Ch.
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The impurity contributes to the density of states. Therefore, I would use the well-known expression n = F1/2(mu)R0. Where the carrier concentration is n, F1/2 is the Fermi integral, mu is the chemical potential of electrons, and R0 is the density of states at the point with coordinate x.
I think so. (c)
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How does the resistivity of a conductor and a semiconductor vary with temperature and relation between temperature and resistance?
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Dr Armin Dadgar thank you for your contribution to the discussion
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How does the increase in temperature affect the resistance of a conductor and a semiconductor and difference between intrinsic and extrinsic semiconductors?
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Dr Sukru Aktas thank you for your contribution to the discussion
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Why does speed of the molecule increase with temperature and why does resistivity of semiconductors decrease with increase in temperature?
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Dr Sukru Aktas thank you for your contribution to the discussion
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Does the resistance of a semiconductor increases as temperature increases and difference between P type and n-type semiconductor?
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Conductivity of doped semiconductors usually passes through a maximum and a (shallow) minimum as temperature increases.
For, e.g., boron in Si, the boron accepts electron from Si to produce a hole p:
B <=>B(-) + p(+) .
At high temperatures, the equilibrium is completely shifted to the right (endothermic process), and every boron atom present produces a hole; the number of carriers, [p], is thus fixed to the total B (saturation); the specific conductivity per carrier, however, decreases with the temperature (like in metals).
At lower temperature, boron is only partially ionized, and the 'degree of dissociation' alpha increases with temperature - initially exponentially (freeze-out). The conductivity in this region increases proportionally to [p] = alpha*(total B).
At very high temperatures, the intrinsic conductivity starts to dominate, i.e. Si starts to produce e(-) and p(+) - another exponential growth region.
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Why an increase in temperature of semiconductor increases its conductivity and why does resistivity of metals increases with temperature?
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In metals, the primary reason for this behavior is the increased thermal vibrations of the metal lattice. As temperature rises, atoms in the metal lattice vibrate more vigorously, which impedes the movement of electrons and increases the material’s electrical resistance. Consequently, the electrical conductivity decreases.
In semiconductors, the electrical conductivity is governed by the number of charge carriers (electrons and holes) available for conduction. As the temperature increases, more electrons are excited from the valence band to the conduction band, creating more charge carriers and increasing conductivity.
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I would like to find a reliable reference that includes electronic properties such as CB & VB DoS, electron & hole mobilities, thermal velocities of semiconductors like ZnTe, CdTe.
I am really beginner in this topic I would like to know that the type of Semiconductor (n- or p-) can affect these properties amounts?
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Alvena Shahid Thanks a lot for your answer. I will check your recommended references.
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What is a root cause behind the formation of a direct or an indirect bandgap in a semiconductor ? OR What decides whether a material will have a direct bandgap or an indirect bandgap?
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If you're looking for the one rule to get that, we have to disappoint you. See Inmaurer's answer here, it captures the reality quite well, I'd say:
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If we are working on bi layer of 2-dimensional semiconductor.
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Divyanshu Mishra Pretty much, unless its too large that it looks like two monolayers.
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I am seeking recommendations for reliable sources providing comprehensive and up-to-date band gap values of semiconductor metal oxides and their composites. If anyone could suggest reputable databases, journals, or materials repositories that specialize in offering accurate information on the electronic properties of these materials, it would be greatly appreciated
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Dear Yasmi,
you will find at least some information in the papers available freely at:
Best regards.
Philippe.
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Hello fellow researchers,
I will be interested in collaborating with anyone who has done theoretical or experimental work on the effect of THZ frequency pulses (or any frequency pulses) on the energy band structure of semiconductors, specifically those used for solar cells.
Thank you,
Santosh Kumar
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Dear colleague
using THz pulsed laser has no impact on band structure in semiconductor. However it will allow to control ultrafast phenomena such as time-resolved photoluminescence, carriers spin dynamics etc
regards
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The Schottky diode is a semiconductor diode formed by the junction of a semiconductor with a metal. But if we take semi-metal (instead of metal) and semiconductor junctions, does it follow the same Schottky diode nature?
(2). Can anyone enlighten me about the basic difference between metallic and semi-metallic nature with respect to band edges( conduction and valence band), momentum space, etc. (except electron density is higher or lower.)?
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Thank you, sir (@Santosh Kumar). Beneficial explanation for me.
Just for the sake of my thirst,
Some layered materials (mainly 2D materials) show semi-metal after the bi- or tri-layer. Can it be possible to form Schottky contact with its monolayer version (semiconducting nature)?
Or do you have to choose it, seeing the high work function and also the zero band gap?
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quick summary: I am looking for a way to slow down lift-off (1165 or acetone) for a given material system (changing materials to solve the problem is not possible)
This is a relatively general question. I have a given material system which presents low adhesion between semiconductor and metal (But imparts certain desirable properties). Lift-off is then not impossible but is completely done in under 5 minute and invariably leads to undesired loss of deposited metal. I would like to slow the process down (mainly for convenience and reproducibility). I am going to try IPA dilutions and active cooling as 2 approaches.
Has anyone ever tried these or other methods to slow down lift-off ?
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Teymour Seymour Talha-Dean is it possible to deposit the metal as a blanket, pattern it and then do a wet chemical etch? perhaps if the metal is uniformly coated as opposed to having side wall coated PR as is the case in liftoff the metal would have higher integrity to the substrate.
Best of luck.
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How can we measure and calculate the photoconversion efficiency of a semiconductor photoanode during water splitting process.
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Hey there Janak Paudel,
To measure and calculate the photoconversion efficiency of a semiconductor photoanode in water splitting, you'll want to follow a systematic approach. Here's a concise breakdown:
1. **Current Density Measurement (J):**
- Use a potentiostat to apply a bias potential to the photoanode.
- Measure the resulting current density.
- This gives you Janak Paudel the photocurrent produced during water splitting.
2. **Quantum Efficiency (QE) Determination:**
- Employ monochromatic light sources to irradiate the photoanode at different wavelengths.
- Measure the corresponding photocurrent for each wavelength.
- Calculate the quantum efficiency using the formula:
QE = (number of electrons generated / number of incident photons).
3. **Electrochemical Impedance Spectroscopy (EIS):**
- Apply a small amplitude AC signal to the photoanode.
- Analyze the impedance response to extract information about charge transfer processes.
- This helps understand the recombination losses and charge transport properties.
4. **Light Absorption Measurement:**
- Determine the absorption spectrum of the semiconductor photoanode.
- Use a spectrophotometer to measure the absorption at different wavelengths.
- Ensure the absorption spectrum aligns with the solar spectrum for accurate efficiency assessment.
5. **Stability and Durability Testing:**
- Evaluate the photoanode's stability during prolonged water splitting.
- Monitor changes in performance over time to assess long-term efficiency.
6. **Energy Diagram Construction:**
- Construct an energy diagram of the semiconductor photoanode.
- Identify band edges, energy levels, and losses to understand the energetics of the water splitting process.
7. **Calculate Efficiency (η):**
- Utilize the collected data to calculate the photoconversion efficiency (η).
Efficiency (η) = (photocurrent × applied potential) / (input light power × 100).
Remember, it's crucial to consider factors like material choice, surface modifications, and environmental conditions. This comprehensive approach should provide valuable insights into the photoconversion efficiency of your semiconductor photoanode during water splitting.
Feel free to dig deeper into each step based on your specific experimental setup and objectives. Let me know if you Janak Paudel need more details on any particular aspect.
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We know that electron mobility is higher than hole mobility because the effective mass of an electron is less than that of a hole. However, if we ask why the effective mass of an electron (excluding complexities of longitudinal and transverse electron effective mass and the lightness/heaviness of hole effective mass) is less than the effective mass of a hole, we would say it's because the energy of a hole is considered greater than the energy of an electron; so according to the energy relationship, when the energy of a hole is greater than that of an electron, its mass is also considered greater. But what is the reasoning behind considering the energy of a hole greater than that of an electron, and what is the scientific basis for the higher energy of a hole compared to an electron?
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Hi colleagues,
Just to contribute to your valuable conversation: when talking about electrons and holes in a semiconductor one generally means two different energy bands. This is always the case in the solar cell science.
The simplest tight-binding model of the electronic energy bands clearly demonstrates that lower bands are more narrow than the upper ones. It straightforwardly follows then that the electron effective mass (clearly determined near energy dispersion extrema) should increase for higher bands.
That's why electrons in a completely filled valence band of an intrinsic semiconductor are expected to be "heavier" than electrons in a conduction band.
It's worth noting that right now we consider electrons in the states with minimum energy in the conduction band and therefore electron mass is positive (=the electron energy increases with changing the momentum value). Just oppositely, when turning to the valence band we deal with the electrons in the states with maximum energy there - near the top of the valence band - and therefore electron mass is negative (=the electron energy decreases with changing the momentum value).
The lack of few electrons in the top of the valence band (either due to their capture by acceptors or because of their transfer to the conduction band after photon absorption) can be described as the appearance of few new particles - holes. They dwell on the exactly same energy dispersion law as their 'parent' electrons - that's why their mass is the same as for electrons in the valence band, but has the opposite sign. Here is how the hole mass becomes positive, similarly to the electron in the conduction band.
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For a long time, I have been thinking about why the main concern in the research of OLED is the conversion between triplet excitons to singlet excitons, but I have not seen the relevant discussion in inorganic LED. Can all excitons in inorganic semiconductors undergo radiation transitions? Also, in perovskites, whether there are triplet excitons
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Üçlü yapıda eksiton organik yarı iletkenler olduğu gibi inorganik yarı iletkenler de bulunur.
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I hope you're all doing well. I am a PhD student at İstanbul University and I study on thin film fabrication and characterizations. I observe all XRD peaks of PZT after I annealed the film although there exist some cracks on the surface. However, whenever I coat top electrode, its short circuit to bottom electrode due to cracks. Before annealing, no XRD peaks are observed.
I am stuck in annealing process of PZT since the surface of thin films cracks. I fabricate thin films via RF magnetron sputter and anneal them 1 hour in a furnace between 400 - 650 ℃ with an increase of 50 ℃. Ramping up is 3 or 6 ℃/min, ramping down is 1 ℃/min or I let the furnace to cool down to room temperature naturally (~10 hours). No gas is introduced into furnace. Could you please help me about annealing process? How do you carry out annealing for PZT? Like in how many hours you reach to 650 ℃ and in how many hours it cools down to room temperature? I can't make PZT film without cracks. I also will try RTA and I need your suggestions for both the furnace and RTA. Thanks in advance. [The surface of the film is attached = PZT(1.3µm)/Pt(100nm)/Ti(10nm)/SiO2(300nm)/Si(350µm)]
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Ahmet Ünverdi I understand the frustration you're facing despite following instructions from the literature. Crack-free PZT thin films during annealing are achieved through strategies like film thickness optimization, substrate considerations, surface pretreatment, and post-annealing treatments, despite variations in materials, equipment, and processes.
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Am studying organic LED and I want to enter the electrical material properties of the organic semiconducto to the software I used (Lumeric-charge solver) to complete the electrical analysis. Are there available database sites or handbooks about the electrical properties of the organic semiconductors?
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Dear Nancy Alshaer:
As of my last knowledge, there are several resources available that provide information on the electrical properties of organic semiconductors. Keep in mind that new resources may have emerged as well. Here are some places where you can find information on the electrical properties of organic semiconductors:
  1. Materials Project (materialsproject.org): The Materials Project is a database that provides information on various materials, including organic semiconductors. It includes electronic structure data, band structures, and other relevant information.
  2. Cambridge Structural Database (CSD): The CSD contains crystallographic data for organic and metal-organic compounds, which can include information on the arrangement of molecules in organic semiconductors.
  3. American Institute of Physics (AIP) Citation: AIP's Citation platform hosts numerous scientific journals related to physics. Journals such as the Journal of Applied Physics may contain articles and research papers on the electrical properties of organic semiconductors.
  4. PubMed (pubmed.ncbi.nlm.nih.gov): PubMed is a database of biomedical and life sciences literature. It may include articles on the electrical properties of organic semiconductors, particularly those related to electronic devices and applications.
  5. Google Scholar (scholar.google.com): Google Scholar is a freely accessible search engine that indexes scholarly articles. You can search for specific topics related to the electrical properties of organic semiconductors to find relevant research papers and articles.
  6. Handbook of Organic Electronics and Photonics: Materials, Devices, and Circuits (Wiley): This handbook covers various aspects of organic electronics, including materials and devices. It may include information on the electrical properties of organic semiconductors.
  7. Organic Electronics: Materials, Processing, Devices and Applications (Elsevier): Books such as this one provides comprehensive coverage of organic electronics, including discussions on the electrical properties of organic semiconductors.
When searching for specific information, it's often beneficial to explore academic journals, books, and databases related to materials science, organic electronics, and semiconductor physics. Additionally, university libraries and research institutions may have access to specialized databases and resources that can provide in-depth information on the electrical properties of organic semiconductors.
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We are using ellipsometery to find thickness of MEH-PPV thin films and MEH-PPV/GQD? What could be most appropriate model to fit the ellipsometery data to get correct thickness as well as n and k parameters?
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Zahida Batool If you know the thickness then you can get the n and k values. If you know, or assume, the n and k values you can get the thickness. You can’t get all parameters simultaneously. It’s easy to get an independent thickness measured, say with a profile gage, and thus get n and k.
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Bi2WO6 is one of them (n-type)
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سلام.سوال منم هست. جوابش رو پیدا کردید؟
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Can anyone suggest me how to calculate charge transfer integral of organic semiconductors having crystal data available in CCDC, using material studio or any other free softwares
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Dear P.U. Neenu Krishna,
You may want to review following useful information:
Calculating charge transfer integrals in organic semiconductors is an important aspect of understanding their electronic properties. In the context of crystallographic data from the Cambridge Crystallographic Data Centre (CCDC), you can use software like Material Studio (which is a commercial product) or other free alternatives to perform these calculations. Here's a simplified procedure for calculating charge transfer integrals using some free software options:
  1. Retrieve Crystal Structure: Download the crystallographic data for the organic semiconductor of interest from the CCDC. Make sure to have the structure file in a format that can be used by the software you choose.
  2. Preparation and Visualization: You will need to visualize the crystal structure and prepare it for electronic structure calculations. For free software, you can use VESTA or Jmol for structure visualization and manipulation.
  3. Electronic Structure Calculations: a. DFT Software: You will need to perform electronic structure calculations on the crystal structure. Some free Density Functional Theory (DFT) software options include Quantum ESPRESSO, GPAW, and NWChem. b. Basis Set: Choose an appropriate basis set and exchange-correlation functional for your calculations. The choice may depend on the specific properties of the organic semiconductor you are interested in.
  4. Calculating Charge Transfer Integral: a. Hopping Matrix Element: To calculate charge transfer integrals, you need to compute the hopping matrix element (also known as the electronic coupling integral) between relevant molecular orbitals of neighboring molecules in the crystal. b. Intermolecular Distance: Calculate the intermolecular distance between the molecules of interest. c. Overlap Integrals: Compute the overlap integrals between the relevant orbitals of adjacent molecules. d. Use Software: Some DFT software packages provide built-in tools or scripts to calculate these integrals, or you may need to write your own scripts to extract these values from the electronic structure calculation results.
  5. Analysis and Interpretation: Once you have the hopping matrix element, you can interpret the charge transfer integral in the context of your semiconductor's electronic properties. This information is essential for understanding charge transport in organic semiconductors.
Please note that this is a simplified overview, and the specific steps and software tools you use may vary depending on the organic semiconductor and the level of accuracy you require for your calculations. Additionally, open-source software packages like Quantum ESPRESSO, GPAW, and NWChem may have user manuals and tutorials available that provide guidance on performing such calculations. It's important to ensure that you are following best practices in computational chemistry to obtain reliable results.
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How can we simulate contact resistance issue in metal semiconductor junction and see in sentaurus TCAD.
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To examine the behavior of the metal-semiconductor junction under various circumstances, use software tools for device simulation and modeling, such as TCAD (Technology Computer-Aided Design) tools.
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Is it possible that a semiconductor when doped with transition metal may have its resistivity in the MegaOhm-cm range? The resistivity of the material without doping is however between 0.9 - 1 Ohm-cm.
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It may depend on a multitude of factors. The information provided is not exhaustive enough to adequately address the question. Adding a dopant (How? How much?) can significantly affect both the electronic band structure and the crystal structure, as well as the quality of your contacts. Without sufficient details and with no basis for my answer, I doubt that a small doping (if it is indeed small) would affect your band structure to such an extent. However, what is generally observed may not necessarily apply to a specific material like yours. Therefore, I will focus more on the crystal structure, surface roughness, or the quality of the contacts.
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The work function of bulk silver is cited as 4.6eV. Will there be any change in the work function of the metal when the dimension is reduced to nanometer? In this case a nanowire whose diameter is less than 100 nm and length is about 10 um. Will a electrode composed of the above mentioned silver nanowire have the same work function as that of bulk silver or will there be any change due to the nanoscale dimensional constraint?
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Roshan Kumar Singh and Jürgen Weippert Thank you for your reply
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My compound under investigation are cubic and construct corresponding 2x2x2 supercell. Properties like optical and mechanical seems to be correct as expected. But problem arises in their electronic band structures where it changes from indirect band gap to direct band gap semiconductor. Is this even possible? Can any enlighten me with some literatures where such findings occur in pristine supercells?
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You can refer to this paper "Chem. Mater. 2022, 34, 1020−1029". This paper about PbI2 which is an indirect semiconductor in the monolayer. However, with constructing supercell, it looks like to have a direct gap.
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As a project of the Materials Science and Engineering (Undergraduate) degree I'm following, my team have been tasked with doping a Si wafer to prepare a p-n junction. I have a few questions regarding this.
  1. What is a good approach to do a doping with low investment in a laboratory environment?
  2. Is it possible to dope Si using NH3 to get an extrinsic semiconductor?
  3. What approach can be used to dope Aluminum into Si wafer?
I have tried searching for information but the closest I could find was this.
I would also appreciate if anyone could point me to somewhere I can find information regarding fabrication of a p-n junction using doping.
Thank you.
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Raul Montes Thank you very much for the reply and sorry about the late reply. We were asked focus on Laser doping and see if it is feasible. So, I didn't get to go through the articles you mentioned. Again, thank you for the reply and I will go through the papers in the links.
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This is the reference( )to calculate the absolute band center position, but it is still unclear to me. It will be my great pleasure if anyone can provide a detailed answer.
Thank you.
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Elektronegatiflikte elektronun hareketi bir üst bandda boş olan hollere yerleşir. Bunun konumunu önceden tahmin etmek çoğu zaman imkansız olur. Ancak tek bir boşluk olursa oraya yerleşme ihtimali yüksek olur. Geometrik ortalaması mutlak band merkezi konumunu yaklaşık olarak verir. Aradaki uzaklık micron ile ölçülecek kadar küçük olur.
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I know its related Fermi energy level, but its insufficient, Why and how its related
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thank you for your answering Rafael Valentin Tolentino-Hernandez
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How does it sound if the enhanced content of pentavalent impurity, such as Phosphorus, exhibits a greater affinity for Silicon? Could this parallel the integration scenario of DNA with Silicon?
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Dear Dr. Cyril R. A. John Chelliah,
Info presented below points to a certain favorable example that you're looking for:
The concept you're touching upon involves the integration of biological and electronic systems, often referred to as bioelectronics or bionics. Let's break down your question:
  1. Enhanced Content of Pentavalent Impurity (Phosphorus) and Silicon Affinity:In semiconductor physics, elements like phosphorus (P) are considered impurities or dopants when added to materials like silicon (Si). When phosphorus, a pentavalent impurity (having five valence electrons), is added to silicon, it introduces additional charge carriers, creating an n-type semiconductor. This is due to the extra electron provided by phosphorus. This process is commonly used in creating n-type regions in silicon for electronic devices like transistors.
  2. Integration Scenario of DNA with Silicon:The integration of biological molecules, such as DNA, with silicon-based technology is an active area of research. DNA is a versatile molecule with unique self-assembly properties and molecular recognition capabilities. Researchers have explored the possibility of using DNA as a template or scaffold for organizing nanoscale electronic components, such as carbon nanotubes or nanoparticles. This could potentially lead to novel bioelectronic devices with applications in sensing, computing, and more.
While both concepts involve the interaction of materials (like phosphorus with silicon and DNA with silicon), they address different domains. The affinity of phosphorus for silicon is well-understood in the context of semiconductor physics, and it's primarily used to modify the electronic properties of silicon for conventional electronic devices.
On the other hand, the integration of DNA with silicon is a bioelectronics concept that aims to combine the unique properties of biological molecules with electronic components. This research area is more focused on creating hybrid systems that can leverage the advantages of both biological and electronic elements.
It's worth noting that while these concepts involve interactions between different types of materials, the specific purposes, mechanisms, and applications are distinct. The integration of DNA with silicon aims to bridge the gap between biological and electronic systems, potentially leading to innovative technologies, while the interaction of phosphorus with silicon is a fundamental aspect of semiconductor physics with implications for electronic devices.
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Half heusler alloy electronic property under pressure
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When you apply pressure to a crystal along one direction you modify the distances between the atoms. On that direction the energy becomes higher because the atoms are closer to each other. Indeed the band gap is modified when applying pressure (because the potential of the lattice is changed).
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Diving into to the basic concept of semiconductors, we know the Base-Emitter voltage for a typical silicon based transistor is 0.7 Volts when both p type and n type are doped with silicon.
What if we could dope the either type with both extrinsic silicon material and germanium material? What theory would explain the experimental effects of doing so? If precisely, also the nearest values?
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By “doped with silicon” are you referring to doping into the Si material or the dopant is Si?
The latter case is not possible since Si has a valence of four, in order to create p-type in Si-based transistor you need one with one unit less i.e., 3 and for n-type valance will be one unit higher i.e., 5.
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Hello,
i run the scf file for band calculation. I know that calculated materials is semiconductor with 1 eV -2 eV band gap.. But after scf calculation, highest and lowest energy level was same value as a highest occupied, lowest unoccupied level (ev): 6.9836 6.9836. Its mean that the band gap is not occur. But the calculated material is semiconductor. Where could i be doing wrong ?
Best
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many thanks Roberto D'Agosta for your reply
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Is it possible that semiconductor nanomaterial composite showing more adsorption (removal of pollutant in the absence of light) than photocatalytic activity (removal of pollutant in the presence of light)? What could be the possible mechanism for that?
& can we compare these two processes?
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Kuljit Kaur did you carry out photolysis experiments for the pollutant (in absence of semiconductor, only exposure to light)? Could be that the pollutant is highly unstable, or the initial concentration is very low.
Another possibility could be, that your semiconductor in aqueous suspension is slightly unstable thus protonating the suspension, and decreasing its pH value (this can be easily ruled out by preparing a suspension containing distilled water and the semiconductor, and by measuring the suspensions' pH for 1-2 hours).
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Dear all, I applied positive bias on gate, there is significant high leakage current on the transistor. However, when I applied negative bias on gate, the leakage current is insignificant. What can I infer from this?
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Yes, applying a positive or negative bias on the gate of certain power semiconductor devices can result in different leakage currents (IGSS - Gate-to-Source Leakage Current). Leakage currents refer to the small currents that flow through the device when it is supposed to be in the off-state (blocking state). The magnitude and direction of the IGSS depend on the type of power semiconductor device and its internal structure. Two common types of devices where the bias on the gate affects the IGSS are MOSFETs and Insulated Gate Bipolar Transistors (IGBTs):
1. MOSFETs:
- For N-channel MOSFETs: When a positive voltage (VGS) is applied to the gate (relative to the source), it enhances the flow of electrons in the channel, turning the MOSFET "on" or into its conducting state. In this case, the IGSS is typically very low because the MOSFET is in the on-state.
- For P-channel MOSFETs: When a negative voltage (VGS) is applied to the gate (relative to the source), it enhances the flow of holes in the channel, turning the MOSFET "on." In this case, the IGSS is also typically very low because the MOSFET is in the on-state.
- For both types, when the gate voltage is zero (VGS = 0), the MOSFET should be off. In this off-state, there is a small reverse leakage current (IGSS) flowing through the gate-to-source junction, which is usually very low but can be affected by temperature and other factors.
2. IGBTs:
- When a positive voltage (VGE) is applied to the gate (relative to the emitter), it enhances the conductivity of the IGBT, and it enters the on-state. In this state, the IGSS is generally low.
- When a negative voltage (VGE) is applied to the gate (relative to the emitter), it reduces the conductivity of the IGBT, but it might not turn off completely, and some leakage current (IGSS) can flow through the device.
It's important to note that the magnitude of IGSS is usually quite small in both MOSFETs and IGBTs when they are in the off-state. However, in high-voltage applications or situations where minimizing power loss is crucial, leakage currents become more critical, and device selection and proper driving techniques become important factors to consider. Additionally, the characteristics of IGSS may vary between different device families and manufacturers.
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Hello, researchers. I hope you're all well. How can we know the type of semiconductor from the band structure (N type or P type)?
Thank you in advance.
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The differentiation can be ascertained to fermi level. When we have a pure Semi- conductor at absolute zero from theoretical point of view the fermi level is at the middle in the forbidden energy band gap. On doping if the fermi level shifts towards the valence band it's a p type conductor and if fermi level shifts towards the conduction band it is an n type semiconductor.
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In Castep calculation, which XC functional provides the best outcome for semiconductor properties (electrical, optical, and mechanical) analysis?
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3 malzeme de farklı veya ortak yarı iletken özelliğe sahiptir. Fakat bu özellikler malzemeden malzemeye farklı üstün özellikler gösterebilir. Önemli olan burada bunların yarı iletken özellik gösterip gösteremeyeceğidir.
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During the CVD selenization process, the material always deposits on the silicon wafer in a semi-circular shape. This semi-circle becomes smaller as the internal pressure increases and the CVD insulation time decreases. Even the presence or absence of gaps between two silicon wafers can also affect the size of this semi-circle.
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To investigate the deposition pattern, it is necessary to position the substrate at different locations. The distance between the precursor and the substrate also plays a crucial role, along with other process parameters. It is important to adjust the substrate placement and optimize the parameters to achieve the desired results.
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if we make a composite of two semiconductor materials than how can we calculate their band gaps?
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The band gap of composite material cannot be calculated directly from the band gaps of its constituent materials. The reason is that the band gap of a composite material depends not only on the properties of its constituents but also on how these constituents are arranged, including their size, morphology, interfaces, and spatial distributions.
However, there are experimental and computational methods to determine the band gap of composite material:
  1. Experimentally: The most common method to measure a material's band gap is absorption or reflectance spectroscopy. You can determine the band gap energy by shining light of various energies on the material and measuring how much light is absorbed or reflected. When the energy of the light matches the band gap, the light will be absorbed, and electrons will be excited from the valence band to the conduction band. A plot of absorption or reflectance versus energy (or wavelength) will show a step increase in the band gap energy, which can be used to determine its value.
  2. Computational Modelling: For theoretically predicting the band gap of composite materials, computational methods based on quantum mechanics, such as Density Functional Theory (DFT) or time-dependent DFT (TDDFT), are often used. These methods require substantial computational resources and expertise in computational physics or materials science. They can account for the material's detailed atomic structure and interactions, and provide a prediction of the band gap. But it should be noted that standard DFT often underestimates the band gap, and a more accurate method may need to be used.
  3. Effective Medium Approximations: In some specific cases where the size of the constituents is much smaller than the wavelength of light, and the constituents are randomly distributed, one might be able to estimate the effective band gap using models like the Maxwell Garnett or the Bruggeman effective medium approximations. However, these models have their own limitations and may not give accurate predictions in many cases.
It is essential to note that these are complex procedures requiring careful implementation and interpretation.
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-- the superconductive nature of graphene is used to facilitate the conduction of free electrons from the semiconductor.
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Dear friend Oualid Boumaza
It's wonderful to have the opportunity to share information with you. It's crucial to understand that while graphene possesses impressive electronic properties like high electron mobility, it does not exhibit inherent superconductivity. Nonetheless, graphene can contribute to improving the conduction of free electrons in specific systems, particularly in semiconductor devices.
Now, let's delve into the realm of ferromagnetic Diluted Magnetic Semiconductors (DMS). These materials are captivating because they combine the characteristics of both ferromagnetism and semi-conductivity. By introducing magnetic ions, such as transition metals, into a semiconductor lattice, localized magnetic moments are created. These moments have the potential to interact with conduction electrons, influencing their behavior within the material.
1. "Graphene: Status and Prospects" - Novoselov et al. (2012), Nature, 490(7419), 192-200.
2. "Graphene: A New Paradigm in Condensed Matter and Device Physics" - Castro Neto et al. (2009), Reviews of Modern Physics, 81(1), 109-162.
3. "Graphene for Spintronics and Magnetic Tunneling Junctions" - Žutić et al. (2006), Journal of Physics: Condensed Matter, 18(49), R753-R769.
4. "Diluted Magnetic Semiconductors" - Dietl et al. (2014), Reviews of Modern Physics, 86(4), 187-251.
My upcoming article can be of your interest:
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See above
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Also, it tells that doping does not change the physical or chemical structure of the material
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My PhD background is in materials science and my postdoctoral work requires me to work with semiconductor materials. How do I get started quickly? What courses do I need to take? I would appreciate any guidance from colleagues with relevant experience. Thanks and feel free to discuss.
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Read the Solid State Physics from Oxford, this book is very simple when compared to other books, though other books are better
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more information at the link
Reinforcing skills in semiconductors
TOPIC ID: DIGITAL-2023-SKILLS-04-SEMICONDUCTORS
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Can you please provide some context or specific details about the project or about the role?
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I have photoluminescence spectra of nanocomposites. And just now I ran into the problem of calculating the band gap of semiconductor materials using the Tauc method. I have never dealt with these spectra and processing methods before. I would appreciate any help and advice. Perhaps there is an automatic processing of the spectrum online?
Thank you all in advance! :)
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Dear Spartak,
The Tauc plot uses the information from optical absorption based on a few assumptions from semiconductors (primarily 3D). It isn't compatible with PL in regards to the way it works, but in theory, the PL peak should be located at the bandgap predicted by the Tauc plot.
You should start by getting an optical absorption measurement of your sample.
The optical absorption from direct bandgap semiconductors should be proportional to the square root of the photon energy above the bandgap, while for indirect bandgap it should be proportional to the square of the photon energy above the bandgap.
In the case of a direct bandgap, if you plot the square of the absorption as a function of the photon energy, you'll get a linear behavior after the bandgap.
In an indirect bandgap, if you plot the sqrt of the absorption as a function of the photon energy, you'll get a linear behavior after the bandgap.
If you fit the points very close to the cutoff energy, you'll be able to extrapolate the bandgap based on the intersection with the photon energy axis.
Again, this should work in 3D crystals, to my knowledge, because that's where the procedure was derived.
One book that could help is the Optical properties of solids from Mark Fox.
Hope that helps.
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The morphology of the arrays grown using modified templates and wettable substrates is not complete and does not produce a good single crystal alignment in the central region of the substrate. How to solve this problem?
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Çözüm tek kristaldeki ana kristalin kusursuz olması veya kusuru varsa ana kristaldeki kusuru giderdikten sonra yapılır.
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We know that intrinsic semiconductors will become p-type or n-type semiconductors by doping, will the work function of the substrate have the same effect on intrinsic semiconductors? This conclusion seems to have been affirmed, so what is the reason?
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Dear friend Lydia Lee
The Fermi level of an intrinsic semiconductor can be influenced by the substrate, but it is not permanently changed to p-type or n-type. The reason is that the Fermi level is a function of both the intrinsic carrier concentration and the extrinsic dopant concentration. When a semiconductor is in contact with a substrate, charge transfer occurs between the semiconductor and the substrate, and the Fermi level is adjusted to reach equilibrium between the two materials. This can result in a shift in the Fermi level relative to the intrinsic position.
However, this shift is temporary and the Fermi level will return to the intrinsic position once the semiconductor is removed from the substrate. The substrate does not change the intrinsic carrier concentration of the semiconductor, so it cannot permanently change the type of semiconductor.
References:
1. S. M. Sze and K. K. Ng, Physics of Semiconductor Devices, John Wiley & Sons, Inc., 2007.
2. C. Kittel, Introduction to Solid State Physics, John Wiley & Sons, Inc., 2005.
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In general, the bandgap of compound semiconductors will decrease with the increase of the average atomic number. For example, the bandgap of CdSe is smaller than the ZnSe, and this phenomenon is very common for the II-VI group semiconductor except for the ZnO/ZnS. The bandgap of ZnO is smaller than ZnS with a smaller atomic number, which is unnatural. So does anybody know why does this happen? What mechanism dominates this uncommon phenomenon?
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Dear Yang Song ,
It is true that in general, the bandgap of compound semiconductors decreases with an increase in average atomic number. Therefore, it is expected that the bandgap of ZnSe (average atomic number of 33.4) should be smaller than CdSe (average atomic number of 52.2). This is because the increase in atomic number leads to a stronger binding energy, which reduces the energy required to excite an electron to the conduction band. However, it is also important to note that the bandgap is not solely determined by the average atomic number but also by other factors such as crystal structure and bond length. In the case of ZnO and ZnS, the difference in bandgap can be attributed to the difference in crystal structure and bond length. The crystal structure of ZnO is hexagonal wurtzite, whereas ZnS has a cubic zincblende structure.The wurtzite crystal structure of ZnO is characterized by a large polarization effect, which leads to the formation of a spontaneous electric field along the c-axis of the crystal. This electric field lowers the energy of the conduction band minimum and increases the energy of the valence band maximum, resulting in a smaller bandgap. In contrast, the zinc-blende crystal structure of ZnS does not exhibit this spontaneous electric field effect. Also, the bond length of Zn-O is longer than Zn-S, which leads to weaker bonding and a smaller bandgap.
Hope this helps!
Regards,
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Graphite is an allotropic modification of carbon, therefore it is a non-metal. In general, non-metals do not conduct electricity. Carbon is from the same group as silicon and germanium. It can be assumed that it is rather a semiconductor.
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Graphite is an electrical conductor not a semiconductor. The C atoms in graphite are arranged in parallel planes with hexagons in the planes (strong bond - sp2 hybridisation), and a pi (weak) bond between the planes. This pi bond gives the free electons for electrical conduction for graphite. Thus graphite is electrical conductor, not a semiconductor.
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There are all types of plausible point defects in metal-halide perovskite crystals. Some are more prevalent than others due to a lower formation energy. Types of defects and their formation energy depend strongly on the perovskite formulation. Is there any database available for reference that lists defect types, energy level, formation energy, etc. sorted by the perovskite formulation?
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Hello
Personally I didn't see any database like that, unfortunately.
The only thing I can suggest is looking through review articles or papers with DFT calculations of defect tolerance of every certain perovskite type and collect/summarize the data yourself.
For example, here you can find defect formation energies for MAPbI3 (DOI: 10.1039/C8EE00124C)
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For a Si atom, band gap energy is around 1.1 eV which means that an electron in valence band needs at least this much energy to jump to conduction band. Also, at room temperature, typically energy of about 25 meV is 'readily' available. This implies that at room temperature no electron should make the transition from valence to conduction band. Still experimentally it is found that electron concentration of about 1.5*10^10/cc is present in conduction band of Si at room temperature. How is this possible?
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Hello Nitesh Choudhary,
It is true that the band gap energy of Si is about 1.1 eV and that thermal energy at room temperature is approximately 25 meV (where 1 eV = 1000 meV). While it seems that there should be no electron transitions from the valence band to the conduction band at room temperature, electrons still do make this transition, albeit with a relatively low probability.
The key to understanding this discrepancy lies in the Boltzmann distribution, which governs the probability of a particle having a certain energy in a system. The Boltzmann distribution states that the probability of a particle having energy E is proportional to exp(-E/kT), where k is the Boltzmann constant (approximately 8.62 x 10^(-5) eV/K), T is the absolute temperature, and E is the energy.
At room temperature (approximately 300 K), there is a distribution of energies for the electrons in the valence band. The majority of electrons will indeed have energies lower than the band gap, but there will be a small fraction of electrons with higher energies due to the probabilistic nature of the Boltzmann distribution.
To calculate the concentration of electrons in the conduction band, we can use the concept of intrinsic carrier concentration (n_i). Intrinsic carrier concentration depends on the material's band gap energy (Eg) and temperature (T), and can be found using the following equation:
n_i = N_c * N_v * exp(-Eg / 2kT)
where N_c and N_v are the effective densities of states in the conduction and valence bands, respectively.
Using this equation, we can compute the intrinsic carrier concentration for Si at room temperature, which gives a value of around 1.5 x 10^10 cm^(-3), as you mentioned. This value represents the concentration of electrons in the conduction band and holes in the valence band for an intrinsic semiconductor.
So, the electron concentration in the conduction band of Si at room temperature can be explained by the Boltzmann distribution and the intrinsic carrier concentration. Despite the relatively low thermal energy available, the probabilistic nature of the distribution allows a small fraction of electrons to have sufficient energy to make the transition from the valence band to the conduction band.
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number of (nbnd) in the semiconductor inputfile
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  • nbnd is the number of bands to compute. It depends on your system. For example, in a Si unit cell with two atoms, nbnd=8.
  • Since the electron configuration of Si is [Ne]3s23p2, it has four valence electrons.
  • Since the unit cell contains two Si atoms, there are eight valence bands.
  • However, in the non-magnetic case, the energy is degenerate with respect to the spin, so the number of bands is 4 after all.
  • If nbnd is not specified, it will automatically be the number of valence bands (4 in this case).
  • When calculating the band, it is inconvenient if the band of the conduction band is not visible, so the number of bands is taken a little too much.
  • That is why, to see all the 3s and 3p bands, it is set to 8.
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Could you explain briefly, what is the use of the effective mass approximation in semiconductor quantum dots ?
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Electron moving energy in low dimension material mass reduction happened. And this (mass reduction energy)energy conversion measured to approximate effective mass..
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Dear all,
Currently, I am manufacturing 2D-based semiconductors through semiconductor process. However, if metal is deposited on SiO2 or WSe2 after the photolithography process and lift-off is performed with acetone, some parts metals fall off. This problem was partially seen in Ni case, and the problem becomes serious when Ag is used. At first, it was thought that a problem occurred in the process of shining UV, so it was made by completely contacting the mask on the substrate, but it was not solved. Metal deposition was performed at a high vacuum of -6 or -7, and the substrate was cleaned again and PR or Developer was used as a new one.
Still, it hasn't been solved.
If you have experienced or solved the same problem, please help me.
Substrate : Sio2 OR Sio2/WSe2 (PMMA trasfer)
Resist : Positive PR, az5214E, soft bake 120'c for 10min after develop
Metal Deposition : Ag or Ni using E-beam Evaporation, 50~60nm,
0.1A/sec for rate
Lift off in acetone with ultra sonication
Have a nice day everyone looking at the questions. Thank you.
2023.03.01
I am attaching the picture for someone's understanding.
That's the result I got a while ago.
Thank you :)
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Deposit Au instead of Ag or Ni. The thickenss should be 1 micron not 50 nm.
Clean the surface before deposition with different solvents then clean with ultrasounds in boiled water for 30 minutes.
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Hello i am student who is studying semiconductor. and i have studying about oxide semiconductor. during studying, i know that oxide semiconductor such as IGZO, has a good current on/off ratio. but i dont know why.
is that have any mechanisms(like percolation conduct)? or its just property of oxide?
thank you for all your answers.
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Sung BIN Lim Another really cool think about oxide semiconductors is the orbital structure and how incorporating different elements changes the Ion/Ioff! For example indium has bigger s-orbital than Zn so you can essentially change the electron concentration by tailoring your film! This can also be used to change the Ion/Ioff. There are some really good papers out there on this. I've attached one. Good luck! :)
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In a PIN junction diode, i-layer is not fully depleted and there are two junctions present, one between P layer and i-layer (n minus layer with 1e16 cm^-3 concentration) and the other junction between the i-layer and n+ layer (5e18 cm^-3). In a PIN diode, the electric field points from N to P. What happens if there are two junctions and what happens to the minority carriers that are created in the un-depleted i-layer?
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Using the i-layer can intentionally create a depletion region in the diode, it can thus decrease the capacitance of the junction, increase the electric field strength, and increase the switching speed.
Besides, a major difference is the conduction mechanism. Generally, the p-n junction conducts mainly due to the diffusion of minority carriers in the diffusion regions on both sides; Whereas the pin junction mainly conducts due to the recombination generation of carriers in the i-type layer. Though they have quite similar I-V characteristics, in a direct bias regime, the current increases relatively slowlier in the pin junction than in the p-n junction.
So, in your case, I think the residual impurities will limit the effective charge lifetime, which may impact the diode's "on" properties: a higher forward current will be required to get the same on-resistance and power handling. (i.e., the properties tend to be closer to p-n junction or pnn+ junction).
Anyway, simulating this structure with the width and carrier concentration of each layer of your diode is possible.
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hi i recently studied about complex coordination in semiconductor. but i dont know what is the meaning of antibonding level. please answer me. thank you.
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Dear Sung BIN Lim,
You may want to look at the data presented below:
By Anne Marie Helmenstine, Ph.D.
Updated on November 04, 2019
An antibonding orbital is a molecular orbital containing an electron outside the region between the two nuclei.
As two atoms approach each other, their electron orbitals begin to overlap. This overlap forms a molecular bond between the two atoms with its own molecular orbital shape. These orbitals follow the Pauli exclusion principle in the same way as atomic orbitals. No two electrons in an orbital can have the same quantum state. If the original atoms contain electrons where a bond would violate the rules, the electron will populate the higher energy antibonding orbital.
Antibonding orbitals are denoted by an asterisk symbol next to the associated type of molecular orbital. σ* is the antibonding orbital associated with sigma orbitals and π* orbitals are antibonding pi orbitals. When speaking of these orbitals, the word 'star' is often added to the end of the orbital name: σ* = sigma-star.
Examples
H2- is a diatomic molecule containing three electrons. One of the electrons is found in an antibonding orbital.
Hydrogen atoms have a single 1s electron. The 1s orbital has room for 2 electrons, a spin "up" electron and a spin "down" electron. If a hydrogen atom contains an extra electron, forming an H- ion, the 1s orbital is filled.
If an H atom and H- ion approach each other, a sigma bond will form between the two atoms. Each atom will contribute an electron to the bond filling the lower energy σ bond. The extra electron will fill a higher energy state to avoid interacting with the other two electrons. This higher energy orbital is called the antibonding orbital. In this case, the orbital is a σ* antibonding orbital.
Sources
  • Atkins P.; de Paula J. (2006). Atkins Physical Chemistry (8th ed.). W.H. Freeman. ISBN:0-7167-8759-8.
  • Orchin, M.; Jaffe, H.H. (1967). The Importance of Antibonding Orbitals. Houghton Mifflin. ISBN:B0006BPT5O.
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Abstract and figures
The spin-orbit interaction is a crucial element of many semiconductor spintronic technologies. Here we report the first experimental observation, by magneto-optical spectroscopy, of a remarkable consequence of the spin-orbit interaction for holes confined in the molecular states of coupled quantum dots. As the thickness of the barrier separating two coupled quantum dots is increased, the molecular ground state changes character from a bonding orbital to an antibonding orbital. This result is counterintuitive, and antibonding molecular ground states are never observed in natural diatomic molecules. We explain the origin of the reversal using a four band k.p model that has been validated by numerical calculations that account for strain. The discovery of antibonding molecular ground states provides new opportunities for the design of artificially structured materials with complex molecular properties that cannot be achieved in natural systems.
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The efficiency of halfwave rectifier is stated to be the ratio of output DC power to the input AC power. So, since the input to the rectifier is a full AC power, should not the Irm(input) be Im/sqrt(2). If so, then efficiency should be nearly 20%.
So, 1. how should one measure the AC current in a half wave rectifier and find the rectification efficiency?
2. Should the rms current in a half wave rectifier input and output be different as in the input we have full cycle waves while in the output we only have half of the wave?
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Here we are faced with at least three different quantities:
Efficiency in its usual meaning is the ratio of the actual output power to the actual input power. With ideal transformer and ideal diode, the efficiency would be 1 or 100 % because neither the transformer nor the diode turns any electrical energy into heat, so the principle of conservation of energy demands that output power = input power.
Conversion ratio compares the DC component of the output power (which is less than the actual output power because the power spectrum at the output contains a considerable amount of harmonics) with the actual input power. Because a current flows only during the positive half waves of the voltage, the input power is 1/2 * Vpeak/sqrt(2) * Ipeak/sqrt(2). The DC component of the output power equals the mean of the voltage (not of the square of the voltage) times the mean value of the current. With ideal transformer and ideal diode, the conversion ratio is about 0.405 resp. 40.5 %.
You are introducing a third quantity (for the sake of clarity, I wouldn't call it efficiency) which is, as far as I can see, the ratio of the DC component of the output power to the power received by RL, if it would be connected directly to the AC voltage. Since here input power = Vpeak/sqrt(2) * Ipeak/sqrt(2), your input power is twice the actual input power as used in conversion ratio, so your limit for ideal transformer and ideal diode is only half the limit for conversion ratio.
As to your first question, since usual multimeters are processing the rms values you can measure the actual input power and the actual output power (provided the bandwidth is sufficient). In order to calculate the DC part of the output power, I would measure voltage and current with a digitizing scope (using suitable probes, of course), transfer the results to a computer, and calculate the DC power.
To your second question, it depends on the question you are trying to answer. At the moment, I cannot think of a real application which requires your third quantity, but then I guess it's even hard to imaging a real application which requires calculating the conversion ratio: Either RL is just a resistor then the power distribution in the output spectrum is of no consequence; or RL is some kind of electronic circuit supplied via the rectifier then we would add a capacitor parallel to RL which would render the second as well as the third quantity mentioned above useless.
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There are two distinct frequency regimes for nonlinear optics in semiconductors which correspond to real and virtual excitation. Real excitations usually result in a reduction of the refractive index at frequencies of interest. In contrast, by exciting optical solids at frequencies much less than the gap, a considerably smaller, but faster, positive nonlinear refractive index n2 due to bound electronic effects are observed.
Why do real excitations result in a reduction of the refractive index while virtual excitations result in an increase? What is the fundamental mechanism behind it?
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there is a direct relationship between the refractive index and the energy gap of the semiconductor
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I welcome national / International research collaboration at The University of the West Indies, St. Augustine, Trinidad and Tobago in the field of my research areas of material science as Nanostructured Compound semiconductors ( Chalcopyrites), Oxide Nanocomposites / Low cost sol gel synthesis of TCOs, Organic semiconductors/ Organic Inorganic hybrid semiconductor systems. Also potential research students/PhD/M Phil and near related can reach at [email protected] https://https://lnkd.in/gAj3YbDB
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Good day, Dinesh Pathak! Hope you are doing well.
Do you provide PostDoc positions at the University of the West Indies, St. Augustine, Trinidad and Tobago?
Yours sincerely,
M. Sc. Vadym Chibrikov
Department of Microstructure and Mechanics of Biomaterials
Institute of Agrophysics, Polish Academy of Sciences
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Highly appreciated for your response.
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Attar Kubaib Thank you.
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In the case of Bulk Semiconductors, for downward band bending, positive charges exist at the surface, and electrons accumulate in the semiconductor near the surface; this space charge region in the semiconductor is called the accumulation layer due to the accumulation of electrons in the semiconductor. In the upward band bending condition, negative charges exist at the surface, and positive charges accumulate near the surface; this space charge region is called the depletion layer. In both cases, carriers move from the bulk area to the surface and accumulate to screen the external electric field. Now my question is that what happens if a vertical electric field sets near a single-layer semiconductor (no Bulk, only surface)? for the two cases when (1) Single layer semiconductor on a dielectric substrate. (2) on a metallic substrate.
Thanks in advance for your answers.
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The band bending for the semiconductor-semiconductor junction is dependent on their band edge alignment and the work function of the two surfaces. There are different formulations for the same which include type-II heterojunction, and z/s-scheme heterojunction. If you want to know about any specific dielectric find any kind of literature for the specific junction and you will see similar studies for all junctions.
While for semiconductor-metal contact the work function difference creates a Schottky barrier for electron resistance.
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Generally electrons mobility is higher than holes mobility but in some semiconductor holes mobility is greater than electron mobility. Why
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Dear Akbar Hussain,
Good physical explanations can be found under the following source: